The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
3 =n
Step-by-step explanation:
-3 +3(n+8)= 2(1 + 6n) - 8
Distribute
-3 +3n +24 = 2 +12n -8
Combine like terms
21+3n = 12n -6
Subtract 3n from each side
21+3n-3n = 12n-3n -6
21 = 9n -6
Add 6 to each side
21+6 = 9n-6+6
27 = 9n
Divide each side by 9
27/9 = 9n/9
27/9 =n
Divide the top and bottom by 3
3 =n
Answer:
y = 1/3x - 1
Step-by-step explanation:
This is because the slope is rise over run. The slope is 1/3 and the y-intercept is -1
Hope this helps
Answer:
Step-by-step explanation:
We want to write the equation of a line that passes through (5, 6) and (-1, 4).
First, let's find our slope. We can use the slope formula:
Let's let (5, 6) be (x₁, y₁) and let's let (-1, 4) be (x₂, y₂). So, our slope is:
Subtract:
Reduce:
So, our slope is 1/3.
Now, we can use the point-slope form, which is:
For consistency, let's let (5, 6) be (x₁, y₁). We will also substitute 1/3 for m. So:
Distribute:
Add 6 to both sides:
Add:
And we're done!
