A salami is 2 3/5 inches long. The salami is cut into 1/8 inch thick slices.

2 answers:

5 0

This is a division problem.
Divide 2 3/5 by 1/8.
First, write 2 3/5 as an improper fraction.
Then divide the fractions.

(2 3/5) / (1/8) =

= (13/5) / (1/8)

= 13/5 * 8/1

= 104/5

= 20 4/5

There were 20 1/8-inch thick slices and one thinner slice at the end.

Eduardwww [97]3 years ago

3 0

13/5 * 8/1 = 104/5 = 20 4/5

104/5 = x/8

5x = 832

X = 166.4

166.4/8 = 20.8

20.8 pieces

You might be interested in

Jody has 3 red marbles 7 blue marbles and 8 yellow marbles what is the ratio red to blue marbles

torisob [31]

Answer:

3/7

Step-by-step explanation:

The ratio is the number of red marbles and the number of blue marbles in a fraction, so the ratio would be 3/7

8 0

2 years ago

Which system of equations could be graphed to solve the equation below? log Subscript 0. 5 Baseline x = log Subscript 3 Baseline

Vanyuwa [196]

You can use the fact that two expressions in equality can be considered to be equal to a third variable(not used in given context).

The system of equations that could be graphed to solve the equation given is

$y = \log_{0.5}(x)\\\\$
$y = \log_3(2+x)$

<h3>How can we form a system of equations from an equation?</h3>

Suppose the equation be $a = b\\$

Let there is a symbol $c$ such that we have $a = b = c$

It is because a and b are same measure (that is exactly what a = b means)

and we gave another name c to that measure.

Thus, we have

$a = c\\b = c$

in addition to $a = b\\$

<h3>Using the above method to find the system of equations needed</h3>

Since the given equation is $log_{0.5}(x) = log_2(2+x)$

The 2d graphs are usually expressed as $y = f(x)$ on X-Y plane.

Taking the equation's expressions equal to y, we get

$log_{0.5}(x) = log_2(2+x) = y$

or, we get system of equations as

$y = log_{0.5}(x)\\\\y = log_3{(2 + x)}$

Their graph is plotted below. The intersection point of both curves is the solution to the given equation as it satisfies both the equations of the system of equations formed from the given equation.

Thus,

The system of equations that could be graphed to solve the equation given is