C=2pir 20pi=2pir 20pi/2pi=2pir/2pi R=10 Height=10/2=5 Two circles surface areas is 2*pir^2 2pi10^2 2*100pi 200pi The cylindrical part is 2pirh 2pi*10*5 100pi Add 100pi+200pi=300pi
The lateral surface area excludes the top and bottom, the <em>bases </em>as they're referred to here. So we have the 9×5 front and back, and the 9×6 left and right sides.
