You want to write this equation in the form (x+...)(x+...) (maybe with a minus sign). To do this, find numbers that, when multiplied, give 16, and when added give -10.
What whole numbers give 16?
1*16 and -1*-16
2*8 and -2*-8
4*4 and -4*-4
Which of these solutions, when changed into a sum, give -10?
Try them one by one and find it is:
-2-8 = -10.
So (x-2)(x-8) is the factorization!
This is really a bit of trial and error, but since most of the time the assignments deals with whole numbers, there aren't that many possibilities.
Answer:
NOCC CD REDSA DFRESB BGF DDDFGFDSDF
Step-by-step explanation:
Answer:
in equation form it is - 8 n ≥ 9
Step-by-step explanation:
<h2>
<u>BRAINLIEST PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!</u></h2><h2>
<u>!!</u></h2><h2>
<u>!!</u></h2>
4 to the right and 3 left
There are infinitely prime numbers "p", but p+2 and p+4 are not primes.
Example: Suppose p = 7 (prime) if you add 2, it becomes 9 (Not a Prime).
Same thing if p = 11(prime), if yo add 4, it becomes 15 (Not a prime number)