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Varvara68 [4.7K]
2 years ago
11

Please help out I can’t really love this

Mathematics
2 answers:
77julia77 [94]2 years ago
6 0
<h3>Answer:   Choice B)  45/56</h3>

========================================================

Explanation:

When we divide two fractions like this, we flip the second fraction and multiply like so...

\frac{5}{7} \div \frac{8}{9}\\\\\frac{5}{7} \times \frac{9}{8}\\\\\frac{5 \times 9}{7 \times 8}\\\\\frac{45}{56}\\\\

which points us to choice B as the answer.

The fraction 45/56 cannot be reduced further because 45 and 56 do not have any factors in common other than 1.

solmaris [256]2 years ago
4 0

Answer:

45/56

Step-by-step explanation:

5/7 ÷ 8/9

Copy dot flip

5/7 * 9/8

5*9 =45

7*8 = 56

45/56

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Forty-two divided by seven plus the quantity three divided by six
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i think its 6.5

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3 years ago
Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
Setler79 [48]

Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

So resulting volume of tank at time t = 400 gallons

Rate of change of salt = inflow - outflow

= 0 - \frac{Q(t)}{400}

i.e. \frac{dQ}{dt} =\frac{-Q(t)}{400}

This is a variable separable equation

\frac{dQ}{Q}=-\frac{dt}{400} \\ln Q = {-\frac{t}{400}} +C\\Q = A e^{-\frac{t}{400}}

Use when t =0 Q = 70

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So A(t) = Q(t) = 70 e^{-\frac{t}{400}} and

A(0) = Q(0) = 70 lbs.

7 0
2 years ago
Plzz help me to solve this qns please
tatiyna

9514 1404 393

Answer:

  ₹14000

Step-by-step explanation:

Let c represent the cost price, and m represent the marked price.

  c × (1 +40%) = m

  m × (1 -15%) - c = ₹1900

Using the first expression for m, the second equation becomes ...

  1.40c×0.85 -c = ₹1900

  0.19c = ₹1900

  c = ₹1900/0.19 = ₹10000

Then the marked price was ...

  m = 1.40c = 1.40×₹10000 = ₹14000

The marked price was ₹14000.

_____

The selling price was ₹11900.

7 0
3 years ago
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