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erica [24]
3 years ago
10

Set up sine, cosine, and tangent for A

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
Sorry but the triangle don’t exit so it’s Yeager for a set up wine
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Solve for x<br><br> 3m,xm,3m,2m
JulijaS [17]
That’s grammatically incorrect
4 0
4 years ago
In rhombus XYZQ below, XZ is 10 centimeters
Zigmanuir [339]
<h3>Diagram in attachment!</h3>

<h2><u>________________________</u></h2>

\begin{gathered}\\ \sf\longmapsto Area\:of\:rhombus=\frac{d_1×d_2}{2}\end{gathered}

  • Diagonal 1 (d1) = 10cm
  • Diagonal 2 (d2) = 4cm

\begin{gathered}\\ \sf\longmapsto Area=\frac{10×4}{2}\end{gathered}

\begin{gathered}\\ \sf\longmapsto Area=\frac{40}{2}\end{gathered}

\begin{gathered}\\ \sf\longmapsto Area=20cm^{2}\end{gathered}

\large\blue{\sf{Option\:C\:is\:correct!}}

8 0
2 years ago
The sum of 5 times a number and 3 is 4
mrs_skeptik [129]

Answer:

5x+3=4

Step-by-step explanation:

I hope this helps.

8 0
3 years ago
Read 2 more answers
Find the distance to the nearest tenth,between S(6,5) and T(-3,-4)
Doss [256]

Answer:

<h3>The answer is 12.7 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(6,5) and T(-3,-4)

The distance between them is

|ST|  =  \sqrt{ ({6 + 3})^{2} +  ({5 + 4})^{2}  }  \\  =  \sqrt{ {9}^{2}  +  {9}^{2} }  \\  =  \sqrt{81 + 81}  \\  =  \sqrt{162}  \\  = 9 \sqrt{2}  \:  \:  \\  = 12.7279...

We have the final answer as

<h3>12.7 units to the nearest tenth</h3>

Hope this helps you

6 0
3 years ago
How to write 224466 with a coma
stira [4]
224,466

hope it helps
3 0
3 years ago
Read 2 more answers
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