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Ber [7]
3 years ago
13

11y^2-19y-10=-4y^2 all real solutions

Mathematics
1 answer:
tangare [24]3 years ago
4 0

Answer:

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

Answer: |

| y = 5/3 or y = -2/5

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stellarik [79]
Hello!

For #1, the LCD is (A) 12 since both numbers go into 12 as their minimal number.

For #2, the missing number is (B) 4 because 1/4*4/4=4/16.

For #3, the answer is (B) 3 because you have to crossmultiply 20n(4*15) to find the answer.

for #4, the correct answer is (A) 4/5 is less than 5/6 because when converted into fractions with a common denominator, 24/30 is less than 25/30.

For #5, the LCD is 36; therefore, the answer is (A) because the fractions in the answer are properly converted to their new denominator.

I really hope I helped!

7 0
4 years ago
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Heather opens a bank account with $125. Each week, starting the following week, she deposits $25 into her account.
vichka [17]
The equation is y=25n+125 I think
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HELP A MEEEE whats 1Million x 1Million
seraphim [82]

Answer:

one trillion

Step-by-step explanation:

5 0
3 years ago
What is y=1/2(x+3)^2+10 in standard form​
anyanavicka [17]

Answer:

Simplified equation in standard form: y=\frac{1}{4}x^{2}+12\frac{1}{4}

Original equation in standard form: y=1/2(x+3)^2+10

Step-by-step explanation:

y=\frac{1}{2}(x+3)^2+10

<u>Step 1: Distribute the </u>\frac{1}{2}<u> :</u>

<u />y=(\frac{1}{2}*x+\frac{1}{2}*3)^2+10<u />

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

<u />

<u>Step 2: Take </u>(\frac{1}{2}x+1\frac{1}{2})<u> and square it :</u>

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

y=(\frac{1}{2}x)^{2} +(1\frac{1}{2})^2+10

y=(\frac{1}{2}x*\frac{1}{2}x)+(1\frac{1}{2}*1\frac{1}{2})+10

y=\frac{1}{4}x^{2}+2\frac{1}{4}+10

<u />

<u>Step 3: Add the constants:</u>

<u />y=\frac{1}{4}x^{2}+(2\frac{1}{4}+10)<u />

<u />y=\frac{1}{4}x^{2}+(12\frac{1}{4})<u />

<u />

<u>Step 4: Get rid of the parenthesis:</u>

<u />y=\frac{1}{4}x^{2}+12\frac{1}{4}<u />

<u />

<u />

3 0
3 years ago
Complete the solution of the equation. find the value of y when x equals to 28<br><br> x+3y=28
Leno4ka [110]

Answer:

y=0

Step-by-step explanation:

If x equals 28 then substitute it in the equation, 28+3y=28

Next, subtract 28 from both sides, 3y=0

Now that you have that its simple, y must equal 0

3 0
3 years ago
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