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3 years ago

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Jenny is making bracelets and necklaces for an Arts and Crafts show. She estimates that she will make less than 50 pieces of jew

elry. The bracelets that she is selling cost $2 and the necklaces cost $3. She would like to make more than $99 in sales.
(graph)

1 answer:

artcher [175]3 years ago

8 0

Answer:

I just need points

Step-by-step explanation:

I just need points

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27.5+3.094+4.86 plz show all steps

marshall27 [118]

27.5 + 3.094 = 30.594
30.594 + 4.86 = 35.454

your answer would be 35.454

hope this helped

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3 years ago

Read 2 more answers

What are Prime numbers?

VikaD [51]

A prime number is a natural number greater than 1 that can't be the factory of multiplying two smaller natural numbers.

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3 years ago

Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list

Radda [10]

Answer:

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: Any from 0 to 5.

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 5, p = 0.3, q = 1 - p = 0.7$

So

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

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3 years ago

Two-thirds of students in a class are girls. If one-half of the girls wear glasses, what fractional part of students are girls w

Fantom [35]

Let's assume the number of students in the class be x.

Given that, Two-thirds of students in a class are girls.

So, number of girls $=\frac{2}{3} x$

Now ne-half of the girls wear glasses. So, one-half of $\frac{2}{3} x$ is

= $\frac{1}{2} *\frac{2}{3} x$

= $\frac{1}{3} x$ Cancel out 2 from both numerator and denominator.

So, one third of the students are girls who wear glasses.

So, the correct choice is E.

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2 years ago

What does mean mean on sports teams

STALIN [3.7K]

Answer:

Physical activy used for pleasure.

Step-by-step explanation:

It's just a meaning so I can't provide an explanation.

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2 years ago