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3 years ago

PLEASE HELP!!please show how you know!

Mathematics

1 answer:

elixir [45]3 years ago

5 0

Answer:

Second and last options are correct answers.

Step-by-step explanation:

Correct options are:

$\huge \frac{(8^3)^2}{8^{-5}}= \purple {\bold {\frac{8^6}{8^{-5}}}}$

$\huge \frac{(8^3)^2}{8^{-5}}= \frac{8^6}{8^{-5}}=\red{\bold {8^{11}}}$

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When the women's soccer team won the state championship, the parent boosters welcomed the team back to school with a balloon b

Julli [10]

Answer:

Each bouquet included 2 foil balloons and 8 latex balloons.

Step-by-step explanation:

Let f represent the number of foil balloons in each bouquet. Then 10-f is the number of latex balloons. The problem statement tells us the cost of all of the bouquets is ...

18(1.94f +0.17(10-f)) = 94.32

We can divide by 18 to get ...

1.94f +1.70 -0.17f = 5.24

1.77f = 3.54 . . . . . . . . . . . . subtract 1.70

f = 3.54/1.77 = 2 . . . . . . . . divide by the coefficient of f

The number of latex balloons is 10-2 = 8.

Each bouquet included 2 foil and 8 latex balloons.

6 0

4 years ago

Find the slope of the line that passes through the points

lesantik [10]

Answer: 1/8

Step-by-step explanation:

1 - 0 = 1

0 - 8 = 8

m = 1/8

3 0

3 years ago

Solve 3/5b = 24 help me

STALIN [3.7K]

You would multiply by the reciprocal (flip the fraction)
5/3 * 24 = 40
b = 40

4 0

4 years ago

Read 2 more answers

2x + 6 = 8 please help meee

grigory [225]

Answer:

x=1

Step-by-step explanation:

2x+6=8

= 2x=2

= x=1

7 0

3 years ago

Read 2 more answers

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago

PLEASE HELP!!please show how you know!​

PLEASE HELP!!please show how you know!