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Ganezh [65]
3 years ago
10

Find the median first quarrile, third quartile, interquartile range, and an outliers for each set of data

Mathematics
1 answer:
Igoryamba3 years ago
3 0
The outlier is 68

The median is 102
First quartile: 87
Third Quartile: 115
The interquartile range is 87-115
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Monica has a $1000 bond with a 5.5% coupon. Monica purchased this bond for $1025. What is the yield of this new bond?
arsen [322]

Answer:

Annual return on the bond is 1000*0.055 = $55 per year  

Yield = return/price = 55/1025 ≈ 0.0537 ≈ 5.4%


6 0
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The ________ is the distance around a circle.
raketka [301]
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A. Write the equivalent fraction for 66% <br>b. Write the equivalent decimal for 89%.​
Schach [20]

Answer:

66/100 (or simplify to 33/50), 0.89

Step-by-step explanation:

7 0
3 years ago
Please help I need to finish my homework
valina [46]

Answer:

AB= 0.625 units (3 s.f.)

∠BAC= 52.9° (1 d.p.)

∠ABC= 32.1° (1 d.p.)

Step-by-step explanation:

Please see the attached pictures for full solution.

- Find AB using cosine rule

- find ∠BAC using sine rule

- find ∠ABC using angle sum of triangle property

4 0
3 years ago
I REALLY NEED HELP
garri49 [273]
Look at the picture.

1.
y=mx+b\\\\m=\dfrac{9}{3}=3\\\\b=4\\\\\boxed{f(x)=3x+4}

2.
f(x)=-2x+3\\\\for\ x=-2\to f(-2)=-2\cdot(-2)+3=4+3=7\to(-2;\ 7)\\for\ x=-1\to f(-1)=-2\cdot(-1)+3=2+3=5\to(-1;\ 5)\\for\ x=0\to f(0)=-2\cdot0+3=3\to(0;\ 3)\\for\ x=1\to f(1)=-2\cdot1+3=-2+3=1\to(1;\ 1)

3.
y=mx+b\\\\m=\dfrac{3}{6}=\dfrac{1}{2}=0.5\\\\b=-3\\\\\boxed{f(x)=0.5x-3}
for\ x=-6\to f(-6)=-6\\for\ x=-2\to f(-2)=-4\\for\ x=0\to f(0)=-3\\for\ x=6\to f(6)=0

4 0
3 years ago
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