Answer:
y≈1.778 (or y=log(3600)/2 or y=log(6)+1)
Step-by-step explanation:
10^2y=3600
log(10^2y)=log(3600)
2y=log(36)+log(100)
2y=log(6²)+2
2y=2log(6)+2
2y-2=2log(6)
y-1=log(6)
y=log(6)+1
y≈1.778
Yes it is greater than 1/2 because 1/2 is worth 50 while 3/5 is 60
Answer:
it's a line
option (b)
Step-by-step explanation:
please mark me as
<h2>
Answer with explanation:</h2>
Given : Sample size
Sample mean :
Sample standard deviation :
Let be the population mean of "like" ratings of male dates made by the female dates.
As per question ,
Null hypothesis :
Alternative hypothesis : , It means the test is a one-tailed t-test. ( we use t-test when population standard deviation is unknown.)
Test statistic:
For 0.05 significance and df =188 (df=n-1) p-value = .001582. [By t-table]
Since .001582< 0.05
Decision: p-value < significance level , that means there is statistical significance, so we reject the null hypothesis.
Conclusion : We support the claim at 5% significance that t the population mean of such ratings is less than 8.00.