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Artyom0805 [142]
3 years ago
14

Need help ASAP! please :)​

Mathematics
2 answers:
vitfil [10]3 years ago
6 0

Answer:

could you make it more clear??

Step-by-step explanation:

I cant really read it

mart [117]3 years ago
4 0

Can you make the photo clearer? Tell me once you do so I can edit this answer :)

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Q1 ).The number of white corpuscles on a slide has a Poisson distribution with mean 4.5.
dybincka [34]

The most likely number of white corpuscles om a slide is 4 ,the probability of obtaining this number 4 is 0.190 , probability of obtaining at least two white corpuscles in total on the two slides is 0.999.

Attending to the first question

<h3>What is Poison Distribution ?</h3>

Poisson Distribution is used for an independent event to find its  probability in a fixed interval of time .

Let X be the number of white corpuscles on a slide, then X~Pois(4.5)

a) We have to find the most likely number of white corpuscles on  a slide , which means expected value of Poise(4.5)

The expected value of Poisson distribution with mean λ is equal to λ.

Therefore the expected value is 4.5.

 the number of corpuscles cannot be non-integer,

To find the most likely number in one experiment,

determine it between 4 and 5.

In the common case P(X=k) when X~Poise(λ) is equal to \frac {\lambda^{k}} {k!}}e^{-\lambda}

,\rm e^{-\lambda}  is a constant in terms of k

​so the point is to find out what is greater  :   {\frac {4.5^4} {4!}} or {\frac {4.5^5} {5!}}

 {\frac {4.5^5} {5!}}={\frac {4.5^4} {4!}} * {\frac {4.5} 5}

{\frac {4.5} 5} < 1

So, {\frac {4.5^4} {4!}} is greater

So, the most likely number of white corpuscles om a slide is 4.

b)  the probability of obtaining this number 4 is

P(X = 4)

= {\frac {4.5^4} {4!}}e^{-4.5}=0.190

c) Let Y be the total number of corpuscles on two screens.

Y=X{\scriptscriptstyle 1}+X{\scriptscriptstyle 2}Y=X1+X2 ,

where X{\scriptscriptstyle 1}, X{\scriptscriptstyle 2}  - number of corpuscles on the first and second slide respectively.

Then Y = Poise(4.5 + 4.5) = Poise(9)

the probability, correct to three decimals places of obtaining at least two white corpuscles in total on the two slides

The goal is to find P(Y ≥ 2)

Therefore the probability less than 2 will be subtracted from the total probability i.e. 1

P(Y ≥ 2 ) = 1 - P (Y=0) - P(Y=1)

= 1-{\frac {9^0} {0!}}e^{-9}-{\frac {9^1} {1!}}e^{-9}=1-10e^{-9}=0.999

To know more about Poisson Distribution

brainly.com/question/17280826

#SPJ1

7 0
2 years ago
(-3,5) is located in
Aleksandr-060686 [28]

It is located in the 2nd quadrant.

(x,y) - 1st quadrant

(-x,y) - 2nd quadrant

(-x,-y) - 3rd quadrant

(x,-y) - 4th quadrant

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align="absmiddle
Jobisdone [24]

\dfrac{1}{9} - \dfrac{5}{6}

  • Set up

\dfrac{2}{18} - \dfrac{15}{18}

  • Get all fractions to a common denominator which will allow you to subtract them

\dfrac{2 - 15}{18}

  • Subtract numerators

\boxed{- \dfrac{13}{18}}

  • Simplify
4 0
3 years ago
PLEASE HELP ASAP I WILL MARK BRAINLIEST
Ray Of Light [21]

Answer:

\large\boxed{density=500\ \dfrac{g}{dm^3}}

Step-by-step explanation:

density=\dfrac{mass}{volume}\\\\1L=1dm^3\\1L=1000mL\to1mL=\dfrac{1}{1000}L=0.001L\\1mL=0.001dm^3\\\\\text{We have}\\volume=12.0mL=12.0\cdot0.001dm^3=0.012dm^3\\mass=6g\\\\\text{Substitute}\\\\density=\dfrac{6g}{0.012dm^3}=\dfrac{6\cdot1000}{0.012\cdot1000}\ \dfrac{g}{dm^3}=\dfrac{6000}{12}\ \dfrac{g}{dm^3}=500\ \dfrac{g}{dm^3}

3 0
4 years ago
Distributive property of-(16-5×)
Anarel [89]
Distribute the negative to the 16 and into the -5
-16+5x
6 0
3 years ago
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