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Strike441 [17]
3 years ago
11

Can some one help please

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0
Y=2/3x-2 is the equation of the line
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I need immediate help!! Picture is the question and my options
soldi70 [24.7K]

Answer:

a = -5.

Step-by-step explanation:

(3x + 2)(x + 1)

= 3x(x + 1) + 2(x + 1)

= 3x^2 + 3x + 2x + 2

= 3x^2 + 5x + 2

So the remainder a = 3x^2 + 5x - 3 - (3x^2 + 5x + 2)

= -3 - 2

= -3 - 2

= -5  (answer)

3 0
3 years ago
In an optical fibre, the power drops by a factor of 10 approximately every 30 km. If the transmit power is 0. 35 W, how far will
IgorC [24]

Answer:

  • 30000 km

Step-by-step explanation:

First convert the transmit power into μW, considering 1 W = 1000000 μW:

  • 0.35 W = 0.35*1000000 μW = 350000 μW

Find how many factors of 10 the power dropped:

  • 350000 / 350 = 1000

Find the distance:

  • 1000*30 km = 30000 km
4 0
3 years ago
Hey, how y’all doing (23 points)
Radda [10]

Answer:

could be better, u?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the product. √5(2+√7) A)2√5+√35 B)√45 C)2√5+2√7 D)√10+√35
OverLord2011 [107]

Answer:

\huge \boxed{2\sqrt{5} +\sqrt{35}}

Step-by-step explanation:

\sqrt{5} (2+\sqrt{7} )

Expand brackets.

\sqrt{5} (2)+\sqrt{5}(\sqrt{7} )

2\sqrt{5} +\sqrt{5} \sqrt{7}

Apply radical rule : \sqrt{a} \sqrt{b} =\sqrt{ab}

2\sqrt{5} +\sqrt{5 \times 7}

2\sqrt{5} +\sqrt{35}

7 0
3 years ago
Read 2 more answers
m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21
AnnZ [28]
The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!
6 0
3 years ago
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