By setting up a system of equations we can easily solve this problem. Let's denote Jane's working hours with x and Jack's working hours with y. Since they don't want to work more than 65 hours, the first equation is x+y=65. The second equation is 14x+7y=770. By solving this system of equation
, we find that y=20 hours, which is Jack's maximum working hours.
Answer:
250 batches of muffins and 0 waffles.
Step-by-step explanation:
-1
If we denote the number of batches of muffins as "a" and the number of batches of waffles as "b," we are then supposed to maximize the profit function
P = 2a + 1.5b
subject to the following constraints: a>=0, b>=0, a + (3/4)b <= 250, and 3a + 6b <= 1200. The third constraint can be rewritten as 4a + 3b <= 1000.
Use the simplex method on these coefficients, and you should find the maximum profit to be $500 when a = 250 and b = 0. So, make 250 batches of muffins, no waffles.
You use up all the dough, have 450 minutes left, and have $500 profit, the maximum amount.
Answer:
1/9 = 0.11111111 ( infinite )
Step-by-step explanation:
P5
From Z tables and at P5 = 5% = 0.05, Z = -1.645
Therefore,
True value = mean +Z*SD = 24.1+(-1.645*2.1) = 20.6455 Chips per cookie
P95
From Z table and at P95=95%=0.95, Z= 1.645
Therefore,
True value = 24.1 +(1.645*2.1) = 27.5545 Chips per cookie
These values shows the percentages of amount of chips in the cookies. Thus, the more the percentage considered, the more the amount of chips in the cookies. This can be used to control the number of chips in cookies during production.
Answer:
1/9, 2/9, 3/9, 4/9, 1/8, 2/8, 3/8, 1/7, 2/7, 3/7, 1/6, 2/6, 1/5, 2/5, 1/4, 1/3.
Step-by-step explanation:
hope this helps,
