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3 years ago

The measure of an exterior angle of a triangle is equal to the sum of the measure of the two ______ interior angles.

Mathematics

1 answer:

Drupady [299]3 years ago

3 0

Answer:

Step-by-step explanation:

The measure of an exterior angle of a triangle is equal to the sum of the measure of the two opposite interior angles.

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Two cars, car X and car Y , start moving from the same point P on a cross intersection. Car X is travelling east and car Y is tr

agasfer [191]

Let the distance traveled by car X be x km
let the distance traveled by car Y by y km 
their paths form a right-angled triangle. 
Let the distance between them be D km 
D^2 = x^2 + y^2 
2D dD/dt = 2x dx/dt + 2y dy/dt 
dD/dt = (x dx/dt + y dy/dt)/D 

at the given case: 
x = 60, y = 80 , dx/dt = 80, dy/dt = 100 
D^2 = 60^2 + 80^2 = 10000 
D = 100 

dD/dt = (60(80) + 80(100))/100 
= 128

5 0

3 years ago

Find the value of x in the triangle shown below HELP ASAP!!!!!

tiny-mole [99]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷ Since this is an isoceles triangle, you can figure it out easily.

We know that the sum of the angles is 180 degrees.

180-56=124

124/2=62

X=62

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

5 0

3 years ago

Express the number 220 as the sum of four numbers that form a geometric progression such that the third term is greater than the

siniylev [52]

Answer:

Step-by-step explanation:

The first four terms of geometric series is:

$a,ar,ar^2,ar^3$

Since, we have given information that the third number is greater than 44 that means:

$ar^2=a+44$

Above equation can be rewritten as:

$a(r^2-1)=44$

Now, using:

$a^2-b^2=(a+b)(a-b)$

Here, a=r,b=1

$a(r+1)(r-1)=44$ (1)

The sum of first four terms is:

$a+ar+ar^2+ar^3=220$

$a(1+r+r^2+r^3)=220$

$a(1(1+r)+r^2(1+r))=220$

$a((1+r)(1+r^2))=220$ (2)

Divide equation (2) by (1) we get:

$\frac{r^2+1}{r-1}=\frac{220}{44}$

$r^2+1=5r-5$

$\Rightarrow r^2-5r+6=0$

$\Rightarrow r^2-3r-2r+6=0$

$\Rightarrow r(r-3)-2(r-3)=0$

$\Rightarrow (r-2)(r-3)=0$

$\Rightarrow r=2,3$

CASE1: When r=2 in $ar^2=a+44$

$a(4)=a+44$

$3a=44$

$a=\frac{44}{3}$

CASE2:When r=3 in $ar^2=a+44$

$a(3)^2=a+44$

$\Rightarrow 9a=a+44$

$\Rightarrow 8a=44$

$\Rightarrow a=\frac{44}{8}=\frac{11}{2}$

The series becomes:

From CASE1: $\frac{44}{3},\frac{44\cdot 2}{3},\frac{44\cdot 2^2}{3},\frac{44\cdot 2^3}{3}$

$\Rightarrow \frac{44}{3},\frac{88}{3},\frac{176}{3},\frac{352}{3}$

From CASE2: $\frac{11}{2},\frac{11\cdot 3}{2},\frac{11\cdot 3^2}{2},\frac{11\cdot 3^3}{2}$

$\Rightarrow \frac{11}{2},\frac{33}{2},\frac{99}{2},\frac{297}{2}$

6 0

3 years ago

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PLEASE HELPPP I'LL GIVE BRAINLY TO WHOEVER ANSWERS CORRECT

erastova [34]

Ok so you are asking a ton of questions... so ima answer some

1. Ben should stop sharing everything. and its 15 shares, carter shared 19.

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3 years ago

Tutorial

Scilla [17]

Answer: y=1/9x-8

Explanation: m= (y2-y1)/(x2-x1)
(-9 - -8) / (-9 - 0) = -1 / -9 = 1/9

1/9x is the slope

B = -8 since it’s x value is 0

So in y=Mx+b form the solution is
Y=1/9x-8

6 0

2 years ago

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