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IrinaVladis [17]

2 years ago

9

“z varies jointly as x and y”

2 answers:

ziro4ka [17]2 years ago

8 0

Answer:

1. z=kxy

2. 36=k(3)(2)

k=6 is the answer

3. 2=k(4)(3)

k= -6 is the answer

z=kxy z=(-6)(8)(6)

z= -288 is the answer

you always remember that the formula we should use is z=kxy

faltersainse [42]2 years ago

6 0

Answer:

urdykdgjjdtdgdmgkgdzkyjt

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all missing assignments are due today and I head help!!!! how many solutions are in y=-4/9x-3 Y=-7/5x-3

fiasKO [112]

Answer

Where is the picture

Step-by-step explanation:

4 0

3 years ago

Simplify.<br> 3^2+ (9-8/2)

solmaris [256]

Hi there! Hopefully this helps!

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Answer: 14.

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First we calculate <u>3 to the power of 2</u> and get 9.

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9 + 9 - $\frac{8}{2}$ = 14.

Now we add<u> 9 + 9</u> to get 18.

18 - $\frac{8}{2}$ = 14.

Then, we<u> divide 8 by 2</u> to get 4.

18 - 4 = 14.

Then we subtract<u> 4 from 18</u> to get.....You guessed it,<u> 14</u>!

3 0

3 years ago

Read 2 more answers

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

PLEASE HELP ME, MY MOM WILL KILL ME IF I DONT HAVE THEESE ASSIGNMENTS DONE

Schach [20]

Answer:

A. 2

B. 10/3

C. 8/3

D. 2/3

Step-by-step explanation: put the whole #and make it into a fraction like this e.g.

6/1 • 1/3 = 6/3 simplifies to 2

3 0

3 years ago

I need help with this math problem!!

11Alexandr11 [23.1K]

Answer:C

Step-by-step explanation:

I had the same question

4 0

2 years ago