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katrin [286]
3 years ago
10

What is the GCF of the numerator & denominator below? (x-2)(x+3)/x^2+4x+3

Mathematics
2 answers:
Ganezh [65]3 years ago
6 0

Answer:

Step-by-step explanation:

Factorize the denominator

Sum = 4

Product = 3

Factors = 1 , 3    {1*3 = 3 and  1+3 = 4}

x² + 4x + 3 = <u>x² + x</u>    + <u>3x + 1*3</u>

                 = x(x + 1) + 3(x + 1)

                 = (x + 1)(x + 3)

GCF of the numerator and denominator = (x + 3)

11Alexandr11 [23.1K]3 years ago
3 0

Answer:

GCD of given expressions is (x+3)

Step-by-step explanation:

let's simply the denominator : -

=》

{x}^{2}  + 4x + 3

=》

x {}^{2}  + 3x + x + 3

=》

x(x + 3) + 1(x + 3)

=》

(x + 1)(x + 3)

so, by plugging (x + 1) (x + 3) in denominator,

=》

\frac{(x - 2)(x + 3)}{(x + 1)(x + 3)}

and here, we can see that the only common factor in both numerator and denominator is

(x + 3)

so, GCD = (x + 3)

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