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Natalka [10]
3 years ago
15

Awser the circled question ​

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

7.5

Step-by-step explanation:

if one square is unit then use area formula for a right triangle which is 1/2bh

since height is 5 and base is 3, 5*3= 15 and 15/2= 7.5

hope this helps

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Which problem matches the equation | 75 ≤ 16x + 10
beks73 [17]

Answer:

B - Jesse practices his guitar for less than 75 hours a month. He practices independently 16 times for x hours and has 10 lessons a month. How many hours could Jesse practice independently each time?

Step-by-step explanation:

Correct me if I'm wrong!!

7 0
4 years ago
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Make sure you show all your work for full points.<br> What is y?<br> yz<br> 42<br> 26<br> 55
svetoff [14.1K]
Y equal 55 .........
7 0
3 years ago
(-7)-(-44)/22+((-4)*59) with calculation
Pavel [41]

Hi,

\frac{ ( - 7) - ( - 44)}{22 + (( - 4) \times 59)}

\frac{  - 7 - ( - 44)}{22 + (( - 4) \times 59}

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\frac{37}{22 - 236}

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good look :)

8 0
3 years ago
Read 2 more answers
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
What is the range for the number of cars, new and used, that were sold from July to December?
sesenic [268]
I think its C cuz it makes more sense then B.
4 0
3 years ago
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