Log_2(log_5 x) =3 show steps
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The answer to this question is (9,13). Here's how:
First thing you need to do is find the equation. You have a coordinate point and the slope. Remember a linear equation or formula is y=mx+b (m= slope and b= y-intercept)
So let's input the slope into the equation:
y=1/2x+b or y=0.5x+b
Notice how there is no b yet? That's because you need to find it. Good thing you have the coordinate points, so replace x and y with it. ( (x,y) = ( -7, 5) )
5=0.5(-7)+b
5= -3.5+b
+3.5 +3.5
b= 8.5
The equation is now y=0.5x+8.5 and with that equation you can now input it in a calculator to find which of the following coordinate points lies on. Or you can just input those points into the calculator. Which I did because I love to show my work. I have a picture of the work included and I really do hope I helped you. If not, message me. I'll be glad you to help you!
First thing you need to do is find the equation. You have a coordinate point and the slope. Remember a linear equation or formula is y=mx+b (m= slope and b= y-intercept)
So let's input the slope into the equation:
y=1/2x+b or y=0.5x+b
Notice how there is no b yet? That's because you need to find it. Good thing you have the coordinate points, so replace x and y with it. ( (x,y) = ( -7, 5) )
5=0.5(-7)+b
5= -3.5+b
+3.5 +3.5
b= 8.5
The equation is now y=0.5x+8.5 and with that equation you can now input it in a calculator to find which of the following coordinate points lies on. Or you can just input those points into the calculator. Which I did because I love to show my work. I have a picture of the work included and I really do hope I helped you. If not, message me. I'll be glad you to help you!