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andreev551 [17]
3 years ago
15

Log_2(log_5 x) =3 show steps

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0
Use the definition of a logarithm
If Log(x) = y ; then b^y = x

Log_{2} (Log_{5} (x)) = 3 \\ \\ 
2^{3} = Log_{5} (x) 
\\ \\ 8 = Log_{5} (x) 
\\ \\ x = 5^{8} 
\\ \\ x = 390,625

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Answer:

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Step-by-step explanation:

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3 years ago
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Calculate the measures of spread for Mrs. Hampton’s class data. Justify your response by describing the process used to find eac
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation: Dot plot for movies seen by a students in a month

To Find : measures of spread

Solution:

Movies frequency cumulative frequency

0 1 1

1 0 1

2 0 1

3 0 1

4 3 4

5 8 12

6 3 15

7 1 16

8 5 21

9 2 23

10 3 26

Range = 10 - 0 = 10

Q2 = (6 + 6)/2 = 6 (13th + 14t)/2

Q1 = 5 7th

Q3 = 8 20th

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5 0
3 years ago
Which is an x-intercept of the graph of the function y=cot(3x)
AveGali [126]

Answer:

x-intercept of the graph of the function y = \cot(3x) is, (\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)

Step-by-step explanation:

Given the function: y = \cot(3x)                        ......[1]

x-intercept defined as the graph crosses the x-axis.

Substitute value of y = 0 in [1] and solve for x;

0 = \cot(3x) or

\cot(3x) = 0

Take the inverse cotangent of both sides of the equation and solve for x;

3x = arccot (0)

We know the exact value of arc\cot(0) = \frac{\pi}{2}

then;

3x = \frac{\pi}{2}

Divide both sides by 3 we get;

x = \frac{\pi}{6}

Since, the cotangent function is positive in the first and third quadrants.

The period of the function \cot(3x) is \frac{\pi}{3} so values will repeat every \frac{\pi}{3}  radians in both directions.

we have;

x =\frac{\pi}{6} \pm \frac{n\pi}{3}

Therefore, the x-intercept of the graph of the function y = \cot(3x)  is ;

(\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)  for every integer n;




5 0
3 years ago
Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square
S_A_V [24]

Answer and Explanation:

Given : Sides of right triangle 5,12 and 13.

To find : Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square ?

Solution :

If 5,12 and 13 are sides of a right angle triangle then

13 is the hypotenuse as it is largest side.

then we take perpendicular as 12 and base as 5.

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Answer:

The mode is 78, for it keeps repeating.

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