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3 years ago

Please help I do anything just help

Mathematics

1 answer:

uranmaximum [27]3 years ago

7 0

Answer:

i think it week 2

Step-by-step explanation:

hope this help

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Line CD passes through points (0, 2) and (4, 6). Which equation represents líne CD?

ladessa [460]

the equation for a line is y = m x + b

using the first set of coordinates (0,2)

2 = m * 0 + b

b = 2

using the second set of coordinates (4,6)

6 = 4 m + 2

4 m = 4

m = 4 / 4

m = 1

use those numbers into the line equation

y = x +2

Answer is: C

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3 years ago

Factorise each of the following.

kupik [55]

Step-by-step explanation:

a) 2(32-4j+8k-jk)

b)a(3a-ab+3c -bc)

c)m(2m - mn + 2n - n^2)

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3 years ago

Raise 7 to the 5th power, then divide the result by j

blondinia [14]

Expression: 7^5/j or solved 16807/j

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2 years ago

A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/

xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$

The degrees of freedom for this sample size are:

$df=n-1=25-1=24$

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.318 \cdot 0.016=0.021$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186$

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0

3 years ago

Why are unbiased estimators preferred over biased estimators?

DIA [1.3K]

Answer:

Generally an unbiased statistic is preferred over a biased statistic. This is because there is a long run tendency of the biased statistic to under/over estimate the true value of the population parameter. Unbiasedness does not guarantee that an estimator will be close to the population parameter.

Step-by-step explanation:

7 0

3 years ago