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2 years ago

Please help I do anything just help

Mathematics

1 answer:

uranmaximum [27]2 years ago

7 0

Answer:

i think it week 2

Step-by-step explanation:

hope this help

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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

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3 years ago

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cluponka [151]

68% due to more 1,2, and 3's

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3 years ago

For every integer k from 1 to 10, inclusive the kth term of a certain sequence is given by [(−1)^(k+1)]∗[1/2^(k)].

jarptica [38.1K]

For every integer k from 1 to 10, inclusive the kth term of a certain sequence is given by [(−1)^(k+1)]∗[1/2^(k)].
If T is the sum of the first 10 terms in the sequence, then T is:

B.

A. Greater than 2
B. Between 1 and 2
C. Between 1/2 and 1
D. Between 1/4 and 1/2
E. Less than 1/4

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3 years ago

Two sides of a triangle measure 9 cm and 23 cm. Which could be the measure of the third side of the triangle?

Verizon [17]

Hello,

Let's be x the length of the 3 side (9,x,23) ==>x>0

Using inequality triangular:

9<x+23==>x>9-23==>x>-14 (done)
x<9+23==>x<32
23<x+9==>x>14

SO 14<x<32

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22 unit cubes and 2 smaller cubes of volume cubic inch each

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