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olga2289 [7]
3 years ago
7

How do you solve 8x-3y=-70 and -2x+5y=-8 using the elimination method please show work.

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

(-11, -6).

Step-by-step explanation:

8x-3y=-70

-2x+5y=-8     Multiply this equation by 4:

-8x+20y=-32

Now add this last equation to the first equation:

17y = -102   - we see that we have eliminated x.

y = -102/17

= -6.

Now plug y=-6 in the first equation to get x:

8x-3(-6)=-70

8x =-70 -18

8x =-88

x = -11.

lora16 [44]3 years ago
3 0

Answer:

6x+2y=-78

Step-by-step explanation:

8x-3y=-70

-2x+5y=-8

6x+2y=-78

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Test the claim that LeBron James and Steph Curry average the same amount of points per game, on average.
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When the variances are known and the sample size is high, a z-test is used to assess if two population means vary. The mean of the two players is not the same.

<h3>What is a Z-test?</h3>

When the variances are known and the sample size is high, a z-test is used to assess if two population means vary.

In order to execute an appropriate z-test, the test statistic is expected to have a normal distribution, and nuisance factors such as standard deviation should be known.

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

\begin{array}{ccl} H_0: \mu_1 & = & \mu_2 \\\\ H_a: \mu_1 & \ne & \mu_2 \end{array}

This corresponds to a two-tailed test, and a z-test for two means, with known population standard deviations, will be used.

(2) Rejection Region

Based on the information provided, the significance level is α=0.05, and the critical value for a two-tailed test is z_c = 1.96

The rejection region for this two-tailed test is R={z:∣z∣>1.96}

(3) Test Statistics

The z-statistic is computed as follows:

\begin{array}{ccl} z & = & \displaystyle \frac{\bar X_1 - \bar X_2}{\sqrt{ {\sigma_1^2/n_1} + {\sigma_2^2/n_2} }} \\\\ & = & \displaystyle \frac{ 30.1 - 25.5}{\sqrt{ {9.112^2/70} + {12.602^2/70} }}  \\\\ & = & 2.475 \end{array}

\begin{array}{ccl} z & = & \displaystyle \frac{\bar X_1 - \bar X_2}{\sqrt{ {\sigma_1^2/n_1} + {\sigma_2^2/n_2} }} \\\\ & = & \displaystyle \frac{ 30.1 - 25.5}{\sqrt{ {9.112^2/70} + {12.602^2/70} }}  \\\\ & = & 2.475 \end{array}

(4.) The decision about the null hypothesis

Since it is observed that |z| = 2.475 > z_c = 1.96, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p = 0.0133p=0.0133, and since p = 0.0133 < 0.05p=0.0133<0.05, it is concluded that the null hypothesis is rejected.

(5.) As it is concluded that the null hypothesis H₀ is rejected. Therefore, there is enough evidence to claim that the population mean μ1  is different than μ2.

Hence, the mean of the two players is not the same.

Learn more about Z-test:

brainly.com/question/15683598

#SPJ1

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---
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