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Ann [662]
3 years ago
6

Find the sixth term of the geometric sequence 9, 18, 36, ...

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

This is a geometric sequence because any term divided by the previous term is a constant called the common ratio. r=36/18=18/9=2 A geometric sequence is expressed as

\begin{gathered}a_n=ar^{n-1},\text{ where a=initial term, r=common ratio, n=term number}\\ \\ a_n=9(2^{n-1})\\ \\ a_6=9(2^5)\\ \\ a_6=288\end{gathered}an=arn−1, where a=initial term, r=common ratio, n=term numberan=9(2n−1)a6=9(25)a6=288

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Pls help I will give brainliest ​
Radda [10]

its B. 50°

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2 years ago
-9 is____ units away from 0 on the number line.
Aloiza [94]

Answer:

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Step-by-step explanation:

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aalyn [17]

Answer:

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3 years ago
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

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b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

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From [3]:

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Factoring:

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Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
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