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riadik2000 [5.3K]
2 years ago
11

What is the volume of a sphere with a radius of 6 mm? sphere v = four-thirds pi r cubed v = 216pi mm3 v = 288pi mm3 v = 512pi mm

3 v = 648pi mm3
Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0

Answer:

V =288 \pi \ mm^3

Step-by-step explanation:

V =\frac{4}{3} \pi r^{3}

   =\frac{4}{3} \pi \left( 6\right)^{3}

   =\left( \frac{4}{3} \right) \times \pi \times 216

   =\left( \frac{4}{3} \right)  \times 216\times \pi

   =288\times \pi

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Freya wants to use her debit card to purchase a $135 tablet computer.
Ray Of Light [21]

Answer:

She must be sure there is at least $135 in her bank account for the purchase.

She must check to see if any automatic payments are scheduled for her account.

Step-by-step explanation:

just finished that assignment

8 0
4 years ago
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
Tanya has a garden with a trench around it. The garden is a rectangle with length 2.5m and width 2m. The trench and the garden t
Drupady [299]

Answer:

5.5m^2

the area of just the trench is 5.5 m^2

Step-by-step explanation:

The Area of trench only is the total area(trench and garden) minus the Area of garden

Area of trench only = total area(trench and garden) - Area of garden

Area = length × breadth

Substituting the given dimensions;

Total area = 3.5 × 3 = 10.5 m^2

Area of garden = 2.5×2 = 5 m^2

Area of trench only = 10.5 m^2 - 5 m^2

Area of trench only = 5.5m^2

the area of just the trench is 5.5 m^2

8 0
4 years ago
Read 2 more answers
The equation and the variable
pav-90 [236]
Variable: $175=P   $40=L   $375=TB
                x=TB-P/L



Equation: $375-$175/$40=5
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5 0
3 years ago
Solve the equation by using quadratic formula . Show your work! Answer maybe in radical or decimal form .
Lorico [155]

Answer:

x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871

Step-by-step explanation:

2x^2+4x-5=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-4\pm\sqrt{4^2-4(2)(-5)}}{2(2)}

x=\frac{-4\pm\sqrt{16+40}}{4}

x=\frac{-4\pm\sqrt{56}}{4}

x=\frac{-4\pm2\sqrt{14}}{4}

x=\frac{-2\pm\sqrt{14}}{2}

x_1=\frac{-2+\sqrt{14}}{2}\approx 0.871,x_2=\frac{-2-\sqrt{14}}{2}\approx-2.871

5 0
3 years ago
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