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netineya [11]
3 years ago
12

How many different codes can a combination lock have if there are 4 numbers on the lock and each number can be from 0-9?

Mathematics
1 answer:
n200080 [17]3 years ago
6 0

Answer:

There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Suprisingly, people have an intense lack of imagination when it comes to choosing codes.

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Which statement best describes the faces that make up the total surface area of this composite solid?
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no

Step-by-step explanation:

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Consider the diagram. The congruence theorem that can be used to prove △LON ≅ △LMN is SSS. ASA. SAS. HL.
s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

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5x - 7(2- 4x) = <br> 8 - 3(6 - 6x) =<br> 9a - 4(2a + 5) =
kati45 [8]

Answer:

the answer to 5x-7(2-4x)= =33x−14

the answer to 8 - 3(6 - 6x) ==18x−10

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Step-by-step explanation:


8 0
4 years ago
The price of an American Airlines ticket to Boston increased to $600. This is a 15 percent increase. What was the old fare? Roun
FinnZ [79.3K]
The old fare was "x"
then it got bumped up by 15%, and the new price is x + 15% of x,
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it, to get 600
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8 0
3 years ago
Exercise is mixed —some require integration by parts, while others can be integrated by using techniques discussed in the chapte
wlad13 [49]

Answer:

\frac{2x^{\frac{7}{2}}}{7}+4x+c

Step-by-step explanation:

We are asked to find the value of the indefinite integral \int \:x^2\sqrt{x}+4\:dx.

Let us solve our given problem applying sum rule as:

\int \:x^2\sqrt{x}\:dx+\int \:4\:dx

\int \:x^2*x^{\frac{1}{2}}\:dx+\int \:4\:dx

\int \:x^{\frac{4}{2}}*x^{\frac{1}{2}}\:dx+\int \:4\:dx

\int \:x^{\frac{5}{2}}\:dx+\int \:4\:dx

Now, we will use power rule.

=\frac{x^{\frac{5}{2}+1}}{\frac{5}{2}+1}}+4x+c

=\frac{x^{\frac{7}{2}}}{\frac{7}{2}}+4x+c

=\frac{2x^{\frac{7}{2}}}{7}+4x+c

Therefore, our required integral would be \frac{2x^{\frac{7}{2}}}{7}+4x+c.  

7 0
3 years ago
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