What is 17 times 5 decided by 8

What is the volume of this rectangular prism?

sergiy2304 [10]

Answer:

$V =\frac{12}{5}\ cm^3$

Step-by-step explanation:

The Volume of Rectangular Prism

Given a rectangular prism of dimensions W, L, and H, its volume is the product of the three dimensions:

V = WLH

The figure shows the dimensions:

L=3 cm

$W=\frac{4}{3}\ cm$

$H=\frac{3}{5}\ cm$

Thus, the volume is:

$V =3*\frac{4}{3}*\frac{3}{5}\ cm^3$

$V =\frac{36}{15}\ cm^3$

Simplifying:

$\boxed{V =\frac{12}{5}\ cm^3}$

5 0

2 years ago

Do me a favor everyone: While you're waiting for an answer to your answer, go through the feed page's questions and report every

azamat

Have a nice day/night <3

4 0

2 years ago

Read 2 more answers

The area enclosed by one shooting circle is 401.92 square yards. Write and solve a formula to find the radius of the shooting ci

Daniel [21]

The formula for area in terms of radius is

... A = πr²

Solving this for r, we get

... A/π = r²

... r = √(A/π) . . . . . formula for the radius

For your given area, the radius is approximately

... r = √(401.92/3.14) = √128 = 8√2

... r ≈ 11.3 . . . yards

7 0

2 years ago

What is the mean of 5,9,6,6,11,8,4

____ [38]

Answer:

7

Step-by-step explanation:

3 0

3 years ago

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ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!

posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 y ², radius y, and thickness ∆y, thus contributing an area of 2π y (3 - 3/4 y ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ y ≤ 2, thus given by the integral

$\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi$

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 x), thus contributing an area of π (√(4/3 x))² = 4π/3 x. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ x ≤ 3, or by the integral

$\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi$

Using either method, the volume is 6π ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0

2 years ago