Answer:
x = 2 ± 2 sqrt(5)i
Step-by-step explanation:
(x – 2)^2 + 20 = 0
Subtract 20 from each side
(x – 2)^2 + 20 -20=0 -20
(x – 2)^2 =- 20
Take the square root of each side
sqrt((x – 2)^2) =±sqrt(- 20)
x-2 = ±sqrt(- 20)
We know sqrt(ab) = sqrt(a) sqrt(b)
x-2 = ±sqrt(- 1) sqrt(20)
We know the sqrt (-1) = i
x-2 = ±i sqrt(4*5)
x-2 = ±i sqrt(4) sqrt(5)
Add 2 to each side
x-2+2 = 2 ±i sqrt(4) sqrt(5)
x = 2 ±i 2 sqrt(5)
x = 2 ± 2 sqrt(5)i
The answer is A
Domain: (0, infinity)
Range: ( - infinity, infinity)
So if you want it to be 9 less than your number (x) then you would subtract nine.
So it would be:
x - 9.
So if your "number" is 12 then you would substitute x for 12 and it would be 12-9. The answer is 3. So 3 is 9 less than a number (12).
I believe
Answer:
20/19
Step-by-step explanation:
y2-y1/x2-x1
= 8-3/5-1/4
=20/19
x^2*(-3x)=-3x^3. The power of x becomes 3 because you add the powers of x. (2+1=3)
