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Gennadij [26K]
3 years ago
7

A. 15 b. 16 c. 9 d. 14

Mathematics
2 answers:
Arada [10]3 years ago
6 0

Answer:

15

Step-by-step explanation:

1-0 =1

3-1 =2

6-3=3

10-6=4

We are adding 1 more each time

10+5 = 15

MAXImum [283]3 years ago
3 0
A. 15
0 +0=0
0 +1 = 1
1+2=3
3+3=6
6+4=10
10+5 = 15
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Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

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8 0
3 years ago
while catching fireflies you and a friend decide to have a competition after m minutes you have 3m + 13 fireflies and your frien
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Hi there, AirConditioning,

The equation we will be using is linear, and takes the form y = slope*x+b, where slope is equivalent to the fireflies caught each minute.

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4 years ago
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Ne4ueva [31]
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3 0
3 years ago
Name five fractions whose values are between 1/2and<br> 7/8
pantera1 [17]

Answer:

9/16 10/16 11/16 12/16 13/16

Step-by-step explanation:

7 0
3 years ago
the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant
Tamiku [17]

Answer:

The rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters is 24\pi \:\frac{cm^3}{s}

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

  • \frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • \frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • The volume of a cone of radius r and height h is given by V=\frac{1}{3} \pi r^2 h

We want to find the rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]

Substituting the values we know into the above formula:

\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}

5 0
4 years ago
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