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pickupchik [31]

4 years ago

11

In which list are the numbers arranged in order from least to greatest? 6/5, 1.5, 1.8, 21/10, 12/5. 4.2, 9/4, 22/7, 2.85, 7/2, 7

/3. 9/5, 1.75, 15/8, 1.23, 5/3. 12/5, 2.04, 13/9, 1.49, 2.4

1 answer:

laila [671]4 years ago

4 0

Answer:

1.5, 1.8, 1.23, 1.49, 1.75, 2.4, 2.04, 2.85, 4.2, 5/3, 6/5, 7/2, 7/3, 9/4, 9/5, 12/5, 12/5, 13/9, 15/8, 21/10

This was confusing haha, anyways hope this helped!

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Which two integers have a difference of 24 and a quotient of -7?

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33- 9=24- -7=17??????

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What is the inverse of the functiob f(x)=1/4x-12

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3 years ago

Please look a the pic<br><br> also you need to find the area

iogann1982 [59]

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Farrah borrowed $155 from her brother. She has already paid back $15. She plans to pay back $35 each month until the debt is pai

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Answer:

It will take 4 months to pay off the dept

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Step-by-step explanation:

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2 years ago

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The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon

Stells [14]

Answer:

(a) $D(q)=\frac{-1}{25} q+148$

(b) $S(q)=\frac{1}{50}q+58$

(c) $p_{*} =88\\\\q_{*} =1500$

Step-by-step explanation:

(a) For the demand equation D(q) we have

<em>P1: 138 Q1: 250</em>

<em>P2: 108 Q2: 1000</em>

We can find <u><em>m</em></u>, which is the slope of the demand equation,

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}$

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

$y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148$

<em>With b: 148 and m: -1/25 we can write our demand equation D(q)</em>

$D(q)=\frac{-1}{25} q+148$

(b) to find the supply equation S(q) we have

<em>P1: 102 Q1: 2200</em>

<em>P2: 102 Q2: 700</em>

<em></em>

Similarly we find <em>m</em>, and <em>b</em>

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}$

$y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\$

<em>And we can write our Supply equation S(q):</em>

$S(q)=\frac{1}{50}q+58$

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing <em>D(q)=S(q)</em>, which means the demand <u><em>equals</em></u> the supply in equilibrium:

$D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\$

$148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\$

We plug 1500 as q into any equation, in this case S(q) and we get:

$S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88$

Which is the equilibrium price p*.

8 0

3 years ago