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Dafna11 [192]
2 years ago
11

Which expressions are equivalent to 5+(-3)(6x-5)5+(−3)(6x−5)5, plus, left parenthesis, minus, 3, right parenthesis, left parenth

esis, 6, x, minus, 5, right parenthesis ?
Mathematics
1 answer:
makvit [3.9K]2 years ago
3 0

The expressions equivalent to 5+(-3)(6x-5)  is -18 x +20 , Option A is the correct answer.

The complete question is

Which expressions are equivalent to 5+(−3)(6x−5)

Choose all answers that apply:

A : -18x+20

B: 3x-3

C: None of the above

<h3>What is an Expression ?</h3>

An expression is a mathematical statement that has variables , constants and mathematical operators all simultaneously.

The expression given is

5+(-3)(6x-5)

By Distributive Property

a(b+c) =ab+ac

5 +  (-3*6x) -(-3*5)

5 - 18x +15

-18 x +20

Therefore Option A is the correct answer.

To know more about Expression

brainly.com/question/13947055

#SPJ1

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Which of the answers are correct? Select all that apply.
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Answer:A, b and also c

Step-by-step explanation:

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3 years ago
Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d
Doss [256]

Answer:

3.83

Step-by-step explanation:

Mean of x = Σx / n

Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2

Sum of square (SS) :

(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8

Mean of y = Σy / n

Mean of y = (101 + 89 + 48 + 21 + 47) / 5 = 61.2

Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8

df = n - 2 = 5 - 2 = 3

Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6

√(Σ(y - ybar)² / df) = √1449.6 = 38.074

Standard Error = √(Σ(y - ybar)² / df) / √SS

Standard Error = 38.074 / √98.8

Standard Error = 3.83

4 0
3 years ago
I need help on number 17 and 18 on how to find the area of the figure
JulsSmile [24]
17. Area of triangle: 1/2bh
1/2 * 12 * 15
1/2 * 180
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3 0
3 years ago
Read 2 more answers
F(x)= 6x-7 g(x)=6x+7, f(g(x))= and g(f(x))=
horrorfan [7]
Can u take a picture please?
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In each of problems 5 through 11, find the general solution of the given differential equation
Brrunno [24]

The complete question is

"Find the general solution of the given differential equation

y''-y=0, y1(t)=e^t , y2(t)=cosht

The function y(t)=e^t  is the solution of the given differential equation.

The function y(t)=cosht is the solution of given differential equation.

<h3>What is a function?</h3>

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

y_1(t) = e^t

Given differential equations are,

y''-y = 0

 So that,  

y' (t) = e^t, y'' (t) = e^t

Substitute values in the given differential equation.

e^t -e^t=0

                   

Therefore, the function y(t)=e^t  is the solution of the given differential equation.

Another function;

y(t)=cosht  

So that,  

y"(t)=sinht\\\\y"(t)=cosht

Hence, function y(t)=cosht is solution of given differential equation.

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2 years ago
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