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3 years ago

8

Geometry help please show work due soon !

1 answer:

Thepotemich [5.8K]3 years ago

4 0

R is 4 if I'm wrong sorry

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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3 years ago

Which pair of lines are parallel? Need to show work

zaharov [31]

Answer:

E

Step-by-step explanation:

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2 years ago

Can someone PLEASE help me solve this equation ? due soon

RideAnS [48]

$\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}$

We know that : (a - b)(a + b) = a² - b²

$\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}$

We know that : 1 - sin²x = cos²x

$\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}$

$\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}$

$\implies \sf{3tanx + 7 = 2sec^2x}$

We know that : sec²x = 1 + tan²x

$\implies \sf{3tanx + 7 =2(1 + tan^2x)}$

$\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}$

$\implies \sf{2tan^2x - 3 tanx - 5 = 0}$

$\implies \sf{2tan^2x - 5tanx + 2tanx - 5 = 0}$

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Help me :)<br> I need help <br> Algebra 2

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