The values of X and Y are 30 and 11 respectively
<h3>How to determine the values of X and Y?</h3>
The figure that represents the complete question is added as an attachment
The given parameters are:
DH = X +3
HF = 3Y
GH = 2X -5
HE = 5Y
From the attached parallelogram, we have:
DH = HF
GH = HE
Substitute the known values in the above equation
X + 3 = 3Y
2X - 5 = 5Y
Make X the subject in X + 3 = 3Y
X = 3Y - 3
Substitute X = 3Y - 3 in 2X - 5 = 5Y
2(3Y - 3) - 5 = 5Y
Expand
6Y - 6 - 5 = 5Y
Evaluate the like terms
Y = 11
Substitute Y = 11 in X = 3Y - 3
X = 3*11 - 3
Evaluate
X = 30
Hence, the values of X and Y are 30 and 11 respectively
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Answer:
3
x
6
+
x
5
−
x
4
−
6
x
3
+
x
2
+
3
x
−
1
Step-by-step explanation:
simp
Answer: The answer is A.|7 + -2 + 5 + - 8|
Step-by-step explanation:
|7−2+5−8|
=|5+5−8|
=|10−8|
=|2|
=2
Answer:
C
Step-by-step explanation:
y= 60(2)+10
y=130
y=65(2)
y=130
Since triangle ADE is similar to triangle ABC and the scale factor is 2, the following relation must be fulfilled:

The, by substituting the given information, we have

By multiplying both sides by x+2, we get

which gives

Then, by subtracting 4x to both sides, we have

and by adding 8 to both sides, we obtain

then, x is given by

Then, by substitutn