Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
Step-by-step explanation:
f(x)=x+4(x^2+2x-3)=4x^2+9x-12
f'(x)=8x+9
f'(x)=0,gives x=-9/8
f(-5)=-5+4(-5-1)(-5+3)=-5+4*-6*-2=43
f(-9/8)=-9/8+4(-9/8-1)(-9/8+3)
=-9/8+4*-17/8*15/8
=-9/8-255/16
=-273/16=-17 1/16
f(5)=4*5^2+9*5-12=100+45-12=133
absolute maximum=133
absolute minimum=-17 1/16
Answer:
25
Step-by-step explanation:
First expression: A= k/M
when A = 15 and M = 5, k = A×M = 75
therefore, when M = 4, A = 75/3 = 25
Answer:
288
Step-by-step explanation:
There are 8 fluid ounces in a cup so that would equate to
8 x 36 = 288
288 fluid ounces a minute
We have an inequation:
x/3 < 3
⇒ x < 3*3
⇒ x < 9
The final answer is x < 9~
