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enot [183]
3 years ago
13

What is the area of the trapezoid below​

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

b. 246

Step-by-step explanation:

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Max caught 43 pounds of fish in one deep-sea fishing trip. The fish needed to be equally separated by weight into 5 packages to
djverab [1.8K]
8.6 would be in one but you could round your answer to 9 or just keep it that way
8 0
3 years ago
Multiply.<br> 4v (3)<br> help?
dsp73

Answer:

12th ...

Step-by-step explanation:

4v (3)

=4v × 3 = 12v

6 0
3 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
3 years ago
What is the solution for this system of linear equations?<br> {23x+4=y<br> 4−2x=y
liubo4ka [24]
We can subsitute since
23x+4=y and
4-2x=y
therefor
23x+4=y=4-2x
so
23x+4=4-2x
minus 4 on both sides
23x=-2x
add 2x to both sides
25x=0
divide both sides by... uh oh
I guess x=0

sub
4-2(0)=y
4-0=y
4=y

the solution is (0,4)
3 0
3 years ago
Can someone tell me what to write please
tiny-mole [99]

Answer: 3.5 years

Step-by-step explanation:  Let A be the salaries earned from company A for x years and B for company B for the same years.

A = 31000 + n*3000

B = 38000 + n*1000

To find the case where A = b, set them to each other and solve for n, the number of years.

31000 + n*3000 = 38000 + n*1000

2000n = 7000

n = (7000/2000) = 3.5 years.

A B

0 31000 38000

1 34000 39000

2 37000 40000

3 40000 41000

4 43000 42000

5 46000 43000

6 49000 44000

7 52000 45000

3 0
2 years ago
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