<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span><span>=<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span></span><span>=<span><span><span>2<span>(<span>x+4</span>)</span></span><span>(<span><span><span>x^2</span>−<span>4x</span></span>+19</span>)
</span></span><span>x+4</span></span></span><span>=<span><span><span>2<span>x^2</span></span>−<span>8x</span></span>+<span>38= is the answer</span></span></span>
Answer:
2(2x-1)/x(x-4)
Step-by-step explanation:
4x^2-14x+6/x^3-7x^2+12x
2(2x^2-7x+3)/x(x^2-7x+12)
2(2x^2-6x-x+3)/x(x^2-4x-3x+12)
2(x-3)(2x-1)/x(x-4)(x-3)
Answer:
y=10
Step-by-step explanation:
what ever x='s you add 5 and what ever y='s you subtract 5
With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes