The standard form of a circle is:

Your center is
and your radius is 
Plug them into the equation and you get


The correct answer is D.
Answer:
P= 150
Substitute P with 150 and you will get 30
Answer:
0.1971 ( approx )
Step-by-step explanation:
Let X represents the event of weighing more than 20 pounds,
Since, the binomial distribution formula is,

Where, 
Given,
The probability of weighing more than 20 pounds, p = 25% = 0.25,
⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75
Total number of samples, n = 16,
Hence, the probability that fewer than 3 weigh more than 20 pounds,





Answer:
It is called the constant ratio.
Tifania’s work is correct because the formula for circumference is 2(3.14)(r)