Use the Pythagorean theorem to find the length of the line

Mathematics

1 answer:

Elanso [62]2 years ago

6 0

Answer:

This is one of my specialties so sit back, relax while I work on this for 5 mins :)

Step-by-step explanation:

The formula is a^2 + B^2 = c^2

Sooo

7^2 + 5^2 = c^2

49 + 25 = 74

√74 = √c^2

8.60232526 = c

8.60232526 rounded to the nearest tenth is 8.6

So there you go. Hope it helps!!

You might be interested in

The ordered pair below is a solution to which equation?

Helga [31]

Hello,

One solution is y=x/9
================

6 0

3 years ago

Determine if the statement is true or false 10,000-99,999<0

a_sh-v [17]

It would be true because 10,000-99,999=-89999 -89999<0 is true

3 0

3 years ago

8z-13=7 what's the number that replaces z

Goshia [24]

All you do is solve for z. So 8z-13=7. To solve for a variable you have to do the opposite to cancel out the numbers on each side. First you add 13 over to 7 to cancel out 13 on the z side. So 8z=20 is what you have left. Then you divide 8 on both sides to cancel out 8 on the z side. what you are left with is z=2.5. Lastly you plug and check. 8(2.5) - 13 = 7, 20-13=7. And thats correct so z is 2.5.

4 0

3 years ago

Read 2 more answers

Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°

umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

$\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ$

6 0

2 years ago

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

TiliK225 [7]

Times it bye 4 thin subtract bye 6

7 0

3 years ago