What factors do 16 and 24 have in common?

50 points. Please quick.

Allisa [31]

Answer:

Condition A.

A rectangle with four right angles

There can be many quadrilaterals satisfying this condition.

Condition B.

A square with one side measuring 5 inches

There can be only one quadrilateral satisfying this condition.

Condition C.

A rhombus with one angle measuring 43°

There can be many quadrilaterals satisfying this condition.

Condition D.

A parallelogram with one angle measuring 32°

There can be many quadrilaterals satisfying this condition.

Condition E.

A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

There can be only one quadrilateral satisfying this condition.

Condition F.

A rectangle with adjacent sides measuring 4 inches and 3 inches.

There can be only one quadrilateral satisfying this condition

Step-by-step explanation:

3 0

3 years ago

Help meeee plz I don’t get it

MatroZZZ [7]

Answer: F

Step-by-step explanation:

This is basically like 2 rectangles. Find the area of both and add them together.

Remember that the area is $l$ x $w$ .

Area of Rectangle 1: $l$ = 7, $w$ = 14

14 x 7 = 98 $cm^{2}$

Area of Rectangle 2: $l$ = 5, $w$ = 14

14 x 5 = 70 $cm^{2}$

Add the areas together: 98 $cm^{2}$ + 70 $cm^{2}$ = 168 $cm^{2}$

6 0

2 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago

The ____ were very similar on the Galapagos and Ecuador

vredina [299]

Answer: I think it’s the plants.

sorry if it’s not right

8 0

2 years ago

A car traveling at a rate of 54 miles per hour. What is the car's rate in feet per secondHow many fect will the car travel in 2

Lena [83]

The car's speed in feets per second is 79.2, Hence, it will cover a distance of 158.4 feets in 2 seconds.

Car's speed in miles per hour = 54 miles per hour

Recall :

1 mile = 5280 feets
1 hour = 3600 seconds

Car's rate in feet per second

54 miles per hour = (54 × 5280 × 1/3600) feet per second = 79.2 feets per second.

Distance in 2 seconds :
Distance = speed × time
Distance = 79.2 × 2 = 158.4 feets

Therefore, the car will cover a distance of 158.4 feets in 2 seconds.

Learn more :brainly.com/question/23774048

7 0

2 years ago