No. Mike wrote the ratio as the amount of change to the new amount. He should have used the ratio of the amount of change to the original amount, which is 55

55/275 , or 20%.

4 0

3 years ago

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The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of

Butoxors [25]

Answer:

$\frac{dN}{dt} =$ λN N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing the information briefly and stating the variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays ( $\frac{dN}{dt}$ ) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :

$\frac{dN}{dt} =$ λN

N(t) = N₀e^(λt) ......equ 1

substituting the value of N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0

3 years ago