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vodomira [7]
3 years ago
14

Using the data: 2, 2, 3, 3, 3, 4, 5, 6, 6, 10

Mathematics
2 answers:
lesya [120]3 years ago
5 0
4.5. you add up all of the numbers, then divide by how many there are and then that’s your answer(round if needed)

in this case:
total=44
44 divided by 10 is 4.4
4.5 is the closest answer :)
sertanlavr [38]3 years ago
4 0

\huge{\boxed{4.5}}

First, add all the numbers together. 2+2+3+3+3+4+5+6+6+10=\bf{44}

Divide by the amount of numbers. \frac{44}{10}=\boxed{4.4}

4.5 is the closest, so that is the answer.

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Can someone help me with this
VladimirAG [237]

Answer:

its red

Step-by-step explanation:

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8 0
3 years ago
In the figure below, segment AC is congruent to segment AB.
jeyben [28]
<span>Triangle ACD is similar to triangle ABD</span>
8 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s. a. Substitute the values into the ver
jasenka [17]
I think it'd be 9 seconds, not 100% sure though.
3 0
3 years ago
Can someone help me pls
Leviafan [203]

Answer:

Step-by-step explanation:

0.75 feet / day [ 1 day / 24 hours] * [12 inches / 1 foot]

This process is called dimensional analysis. The trick it uses is to cancel out units (like feet or days ) where possible. In this case, 1 day is going to cancel out and leave behind 24 hours. 1 foot will cancel out and leave behind 12 inches.

It is well worth learning how to do this, because the process is done in the higher sciences.

So what you are left with is

0.75 * 12 inches / 24 hours

0.75 inches /hour * 1/2

0.375 inches / hour.

6 0
3 years ago
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