Pwese Math suks lol and I didn't learn this
1 answer:
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Answer:
Step-by-step explanation:
6g + 4a = 7a
⇔ 6g = 7a - 4a
⇔ 6g = 3a
Divide both side by 6a
⇒ ⇔
I hope this will help you.
I did not get any zeros since the graph doesn’t cross the x axis, meaning that there are no rational zeros
However, here is the method u can use to find the zeros lol
You can use the quadratic formula in order to get the zeros
This is the equation therefore use these values
ax^2+bx+c=0
A=1
B= -5
C=12
The quadratic formula is -b±√(b^2-4ac))/2a (I left a picture just in case)
However, here is the method u can use to find the zeros lol
You can use the quadratic formula in order to get the zeros
This is the equation therefore use these values
ax^2+bx+c=0
A=1
B= -5
C=12
The quadratic formula is -b±√(b^2-4ac))/2a (I left a picture just in case)