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Andrew [12]
3 years ago
10

Standard form of -43/63 is​

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

7.28 × 1013

Step-by-step explanation:

The standard form of a number is introduced to avoid the difficulty of reading the large numbers. Any number that can be written in the decimal form between 1.0 to 10.0 multiplied by the power of 10.

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Pleaseee help <br><br> What choices are real numbers? Check all that apply.
7nadin3 [17]

Answer:

what  you arest mine but the other one says no answer what

Step-by-step explanation:

6 0
3 years ago
There are 40 people at Drake’s sweet sixteen party. Drake’s only rule is that everyone in the party must meet and shake each oth
Nonamiya [84]

Answer:

Given:

Total Number of people at the Drake’s sweet sixteen party = 40

Everyone in the party must meet and shake each other’s hand

1) How many handshakes are there altogether?

There was total of 780 handshakes in the party.

2. How did you get your solution:

If you have 7 people, person seven shakes six other hands, person  

six shakes five other hands, person five shakes fours other hands,  

person  ,four shakes three other hands, person three shakes two other hands,  and person two shakes one hand.  Another way to see it is,

Person 7  +person 6 + person 5 + person 4 +person 3 + person 2 +  person 1

= 6+5+ 4+3+2+1

=>21

so similairly in case of 40 persons

= 39+38+37+36+37+36+35+34 .................+3+2+1

=>780

3) What’s the quickest way to figure this out if Drake invited 1,000 people?

People at Party               Number of Handshakes

     2                                                     1

     3                              1 + 2              = 3

     4                            1 + 2 + 3          = 6

     5                          1 + 2 + 3 + 4      = 10

     6                        1 + 2 + 3 + 4 + 5  = 15

     .

     .

     .                                          

     n                              1 + 2 + ...+ (n-1) =  --------     \frac{n(n-1)}{2}

Hence for n persons the number of handshakes will be  \frac{n(n-1)}{2}

So for 1000 persons the number of handshakes will be

=>\frac{1000(1000-1)}{2}

=>\frac{1000(999)}{2}

=>\frac{999000}{2}

=>499,500

                                                     

3 0
3 years ago
Henry is mixing concrete. To make concrete he needs to mix cement, sand and gravel in the ratio 1 : 4 : 7 by weight. Henry needs
jolli1 [7]

Answer:

Henry is short of gravel

Step-by-step explanation:

Here, we are to identify which of the ingredients Henry is short of.

To identify this ingredient, what is needed to be done is to share the 180kg of concrete appropriately to get which of the material does not meet its ratio and thus allowing us know which is insufficient.

The total ratio is 1 + 4 + 7 = 12

For cement, we have ;

1/12 * 180 = 15 kg

For sand, we have

4/12 * 180 = 60kg

For gravel, we have

7/12 * 180 = 105 kg

From the values in the question, we can see that all the values we have are greater what is shared in the ratio except in the case of gravel. So we can confidently say he is short of gravel

8 0
3 years ago
Hi I am in desperate need of a "tutor" If anyone is decent at Algebra II, any little help is welcomed! Please respond to this an
Llana [10]

Answer:

Step-by-step explanation:

Hi,

I am quite good at maths and will be happy to help you, not just in Algebra, but any other topics in maths

6 0
3 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
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