Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
Answer:
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Step-by-step explanation:
i got it right
Answer:
Angle 5
Step-by-step explanation:
Adjacent angles share a common side and a common vertex.
Y1 is 3x, y2 is x^3 and y3 is 3^x