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Lesechka [4]
4 years ago
13

Y=mx-b Everyone has +b but not -B Please helppp

Mathematics
1 answer:
Stolb23 [73]4 years ago
8 0
Hope this helps you out !

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Does anyone know how to solve this? Please helppp, I’m so confused
netineya [11]

Answer:

easy

y = 65 because it's an isosolese triangle

x = 50 because sum of interior angles equals 180

7 0
2 years ago
Read 2 more answers
Which values are in the solution set of the compound inequality? Select two options
zhannawk [14.2K]

The values are in the solution set of the compound inequality are (-6, -3), (3, 8).

<h3>What is inequality?</h3>

Inequality is the phenomenon of unequal distribution of resources and opportunities among the given function.

To find the number that are solutions to the compound inequalities, the value of x is

First inequality:

4(x +3) ≤0

4x +12 ≤0

4x ≤-12

x ≤-3

The value of x lies in the interval = (-∞ , -3]

Second inequality:

x +1 >3

x>2

The value of x lies in the interval = (2 , ∞)

So, the interval solution is (-∞ , -3] U (2 , ∞)

Thus, the values are in the solution set of the compound inequality are (-6, -3), (3, 8).

Learn more about inequality.

brainly.com/question/20383699

#SPJ1

7 0
2 years ago
Plz help!!! Urgent!!! It is a mathematics question, I had attached an picture here.
Marianna [84]
B and (0,4)
because the 0 is the x intercept where it crosses 
5 0
3 years ago
Read 2 more answers
I have a total of 29 coins-they are quarters and dimes. Together they amount to $5.60. How many quarters do I have? How many dim
Anna007 [38]
450/25= 18

where 450 is $4.50 and 25 is one quarter. there will be 18 quarters. 

560-450=110

110/10=11

where 110 is $1.10 and 10 is one dime. there will be 11 dimes. 

11+18= 29

where 11 is total number of dimes and 18 is total number of quarters. and 29 is total number of coins
6 0
3 years ago
Read 2 more answers
RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A
Anna [14]

Answer:

Option A. 10\ units^{2}

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

A(-3,1),B(-2,-1),C(2,1),D(1,3)

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance AD</em>

A(-3,1),D(1,3)

substitute in the formula

AD=\sqrt{(3-1)^{2}+(1+3)^{2}}

AD=\sqrt{(2)^{2}+(4)^{2}}

AD=\sqrt{20}

AD=2\sqrt{5}\ units

<em>Find the distance AB</em>

A(-3,1),B(-2,-1)

substitute in the formula

AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}

AB=\sqrt{(-2)^{2}+(1)^{2}}

AB=\sqrt{5}

AB=\sqrt{5}\ units

Find the area

A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}

4 0
3 years ago
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