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3 years ago

HELP!!! =∆=Applying the Pythagorean theorem, solve this triangle.

Mathematics

2 answers:

Digiron [165]3 years ago

4 0

Answer:

c = sqrt(106)

Step-by-step explanation:

Since this is aright triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2 + 9^2 = c^2

25 +81 = c^2

106 = c^2

Taking the square root of each side

sqrt(106) = sqrt(c^2)

c = sqrt(106)

neonofarm [45]3 years ago

4 0

Therefor y=10.29 which is hypotenuse of the triangle

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Solve and graph the following compounf inequalities 7<5x+2<22

Digiron [165]

1<x<4 is the answer for the question

7 0

3 years ago

Read 2 more answers

A. ∠2 B.∠5 C.∠4 D.∠3

Shkiper50 [21]

The answer is D.∠3
If you use a proctor you can see they measure the same

6 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to

aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x $10^{8}$ square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x $10^{4}$ Km.

Surface area of the star = 4 $n^{2}$

Where n is the radius of the star.

So that;

n = $\frac{ 1.8083 * 10^{4} }{2}$

= 0.90415 x $10^{4}$

n = 0.90415 x $10^{4}$ Km

Thus,

Surface area = 4 x $(0.90415*10^{4} )^{2}$

= 326994889

Surface area = 3.2700 x $10^{8}$ $km^{2}$

Therefore, the surface area of the star is 3.2700 x $10^{8}$ square kilometres.

4 0

3 years ago

If x. 5x and 6x are the measures of the

max2010maxim [7]

Answer:

Since one of the angles is 90°, the triangle is right.

Step-by-step explanation:

Angles in a Triangle

The sum of angles in a triangle is 180°. We are given the angles are x, 5x, and 6x, thus:

x + 5x + 6x = 180

Simplifying:

12x = 180

Dividing by 12:

x = 180/12 = 15

x = 15°

5x = 75°

6x = 90°

Since one of the angles is 90°, the triangle is right.

6 0

3 years ago

HELP!!! =∆=Applying the Pythagorean theorem, solve this triangle.​

HELP!!! =∆=Applying the Pythagorean theorem, solve this triangle.