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2 years ago

7

What is 6 4/9 as an improper fraction

2 answers:

Arte-miy333 [17]2 years ago

5 0

Answer:

58/9

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Katarina [22]2 years ago

4 0

Answer: 58/9

Step-by-step explanation:

Turn 6 into an improper fraction.

6x9 = 54

54/9 + 4/9 = 58/9

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Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

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2 years ago

Find the measurement

xenn [34]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$6z + 7 = 8z - 9$

$8z - 9 = 6z + 7$

Add sides 9

$8z - 9 + 9 = 6z + 7 + 9$

$8z = 6z + 16$

Subtract sides 6z

$- 6z + 8z = - 6z + 6z + 16$

$2z = 16$

Divide sides by 2

$\frac{2z}{2} = \frac{16}{2} \\$

$z = 8$

Thus ;

$NP = 8z - 9$

$NP = 8(8) - 9$

$NP = 64 - 9$

$NP = 64 - 4 - 5$

$NP = 60 - 5$

$NP = 55$

Done...

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3 years ago

Before she started hiking, Jessica’s altimeter read +250 meters. She climbed 200 meters and reached point A, which is at an elev

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Point A altimeter reading: +450

Point B altimeter reading: -50

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Need help with numbers 5-12

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5. Positive
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2 years ago

What is the inverse equation for h(x) = 2log(x-3) ?

marshall27 [118]

Given the function:

$h(x)=2log\left(x-3\right)$

To find its inverse:

$\begin{gathered} y=2log\left(x-3\right) \\ x=2log\left(y-3\right) \end{gathered}$

solving for y:

$\frac{x}{2}=log(y-3)$ $\begin{gathered} 10^{\frac{x}{2}}=y-3 \\ \\ 10^{\frac{x}{2}}+3=y \end{gathered}$

ANSWER

$h^^{-1}(x)=10^{\frac{x}{2}}+3$

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11 months ago