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nadya68 [22]
3 years ago
13

Assuming all model requirements for conducting the appropriate procedure have been​ satisfied, is the mean IQ of the students

in the​ professor's statistics class higher than that of the general​ population, 100? Explain what statistical procedure should be used for this research objective.
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

Step-by-step explanation:

The right statistical procedure is by applying a hypothesis test that uses a single mean. Here, if we are to talk about comparison, it should be between the mean IQ of the students in the class and the national average IQ. The class is not for a comparison between two population means because it is viewed as the sample of the population. That is to say, the required task is to determine if the sample mean is greater than the population mean. We can conclude that this obeys a hypothesis test rather than a confidence interval.

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3 years ago
Prove that the value of the expression<br> (16^3–8^3)(4^3 +2^3) is divisible by 63.
Darya [45]

Answer:

Step-by-step explanation:

16^3 - 8^3

Take out 8^3 as a common factor.

16^3 = 2^3 * 8^3

8^3(2^3 - 1)  

8^3(8 - 1) = 8^3 * 7

(4^3 + 2^3)     Expand

64 + 8            Combine

72

72 = 9 * 8

Conclusion

(8*3 * 7 )(9*8)

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So any number containing 63 will divide into the reduced form of

(16^3–8^3)(4^3 +2^3)

7 0
2 years ago
But The aquarium charges $12 per ticket for adults and $5per ticket for children. A group of 90 children and adult chaperones vi
White raven [17]

Answer:

There were 76 childrens and 14 adults.

Step-by-step explanation:

Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:

children + adults = 90

Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:

5*children + 12*adults = 548

With these two equations we have a system of equations shown below:

children + adults = 90

5*children + 12*adults = 548

In order to solve this we will multiply the first equation by -5, and sum both equations we have:

-5*children - 5*adults = -450

5*children + 12*adults = 548

7*adults = 98

adults = 98/7 = 14

children + 14 = 90

children = 90 - 14 = 76

There were 76 childrens and 14 adults.

7 0
3 years ago
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