Answer:
a)J = 450,000 +(20% * C)
b)C =250000+ (50%*J )
c)J = 450000 + {20%* [250000+(50%*J)}
Explanation:
a)J = 450,000 +(20% * C)
This represent the total cost of Janitorial Department due to the fact that 450000 is a direct cost of janitorial department plus 20% of total cost of Cafeteria department allocated to Janitorial department.
b)C =250,000+ (50%*J )
This represent the total cost of cafeteria Department due to the fact that 250,000 is a direct cost of cafeteria department plus 50% of total cost of Janitorial department allocated to cafeteria department.
c)
Substituting the value of C determined in part b in part a
J = 450,000 + {20%* [250,000+(50%*J)}
Therefore in place of C in equation 1 ,the value of c determined in equation 2 is thereby substituted .
Answer:
$230,899
Explanation:
Calculation for what the equivalent present cost is for the first 5 years
Present cost of the repair work = 68,000 * (P/A, 6%,5) - 7,000 * (P/G, 6%,5)
Present cost of the repair work= 68,000 * 4.212364 - 7,000 * 7.934549
Present cost of the repair work= $230,898.90 Approximately $230,899
Therefore the Present cost of the repair work will be $230,899
All salaries related to the factory
15,000+98,000=113,000
Answer: Paper Forms
Reason: Process of Elimination and Educated Guess (Also, I just learned this)
