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mariarad [96]
2 years ago
12

What is the solution for x in the equation? -2x + 14 + 10x = 34 A. X=6 B. X=2/5 C. X=1/8 D. X=5/2

Mathematics
1 answer:
julsineya [31]2 years ago
5 0

Answer:

Step-by-step explanation:

x =(10-√-800)/2=5-10i√ 2 = 5.0000-14.1421i

x =(10+√-800)/2=5+10i√ 2 = 5.0000+14.1421i

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HELP<br> Find the value of two numbers if their sum is 5 and their difference is 30
vodomira [7]

Answer:

The 2 numbers are -12.5 and 17.5.

Step-by-step explanation:

Let 1 number be x then  x - y  = 30 where the other number is y.

y = x - 30 so the sum is:

x - 30 + x = 5

2x = 35

x = 17.5

and y = 17.5 - 30 = -12.5.

8 0
3 years ago
Read 2 more answers
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
What do you call -6 and 6
Oduvanchick [21]
The first one is negative six and the second one is positive six
5 0
3 years ago
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Given that y is directly proportional to x. If y = 30 and x= 5, write an equation that connects y with x.
Licemer1 [7]

Given:

y is directly proportional to x.

y=30 when x=5

To find:

The equation that connects y with x.

Solution:

It is given that, y is directly proportional to x. So,

y\propto x

y=kx                     ...(i)

Where, k is the constant of proportionality.

We have, y=30 when x=5. Substituting these values in (i), we get

30=k(5)

Divide both sides by 5.

\dfrac{30}{5}=k

6=k

Substituting k=6 in (i), we get

y=6x  

Therefore, the required equation is y=6x.

8 0
2 years ago
Hi need help?????!!!
Juliette [100K]

D

C

Sorry if both aren't correct, it's been a while since i did this...

6 0
3 years ago
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