Whatever the answer is...whats the question
I will assume you mistyped this question. For y = -1/16x^2 + 4x + 3, the answers to this question are
a) 3 feet
b) 67 feet
c) 64.741 feet
For a) we note that at x = 0, that is the instant where the ball leaves the hand. y(0) = 0.
For b), we find the vertex of y = -1/16x^2 + 4x + 3
y = -1/16x^2 + 4x + 3
y = -1/16(x^2 - 64x) + 3
y = -1/16(x^2 - 64x + 1024 - 1024) + 3
y = -1/16((x-32)^2 - 1024) + 3
y = -1/16(x-32)^2 + 64 + 3
y = -1/16(x-32)^2 + 67
The vertex is at (32,67) so 67 is the maximum height.
For c), we find the x-intercepts with the quadratic formula on
y = -1/16x^2 + 4x + 3=0:
x = [ -b ± √b^2 - 4ac ] / (2a)<span>
x = [ -4 ± √4^2 - 4(-1/16)(3) ] / (2(-1/16))
x = -0.741, 64.741
Only the positive solution, so 64.741 feet </span>
The answer is 2k^2 - 7k - 4 because 2k x k is 2k^2 and 2k x (-4) is -8k and 1 x k is k and 1 x (-4) is -4. So then you would get 2k^2 - 8k + k - 4 which simplifies to 2k^2 - 7k - 4 which is your answer.
Answer:
Length of the rectangle is = 8 inches.
Step-by-step explanation:
Given :
Area of square = Area of the rectangle
According to the question:
Length of the square be 'x'.
Its area = (Side)*(Side) =
...equation (i)
Length of the rectangle = 
Width of the rectangle = 
Area of the rectangle =Length * Width
⇒
⇒
...equation (ii)
Equating both the equation as area of both the figure are equal.
⇒ 
⇒ 
...subtracting both sides
⇒ 
...dividing both sides with 2
⇒ 
inches
Plugging the value of x=4 in the length of the rectangle.
We have,
⇒
So the length of the rectangle = 8 inches.
The answer is B: <span>choosing five CDs where not all of them are pop</span>
