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2 years ago

Steves pattern: 4, 25, 130, 665. what is steves pattern?

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

7 0

Answer: (4+1)*5=25; (25+1)*5=130; (130+1)*5=655.

Step-by-step explanation:

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Jeremy unpacked 18

tekilochka [14]

Answer:

Step-by-step explanation: 40 x .45 = 18

7 0

2 years ago

If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.

Cloud [144]

Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0

2 years ago

Read 2 more answers

You have a mean score of 84 after taking five 100-point tests. What do you need to score on the sixth 100-point test to have a m

kap26 [50]

The mean of n numbers is the sum of the numbers divided by n.

You have a mean score of 84 after taking 5 tests. Let x be the sum of scores.
$\frac{x}{5}=84 \\
x=84 \times 5 \\
x=420$
You scored a total of 420 points on five tests.

You need to have a mean score of 85 after taking 6 tests. Let y be the score you need to obtain. Your total score on 6 tests is 420+y.
$\frac{420+y}{6}=85 \\
420+y=85 \times 6 \\
420+y=510 \\
y=510-420 \\
y=90$

You need to score 90 points on the sixth test.

8 0

2 years ago

Read 2 more answers

The perimeter of an equilateral triangle is at most 72, what would this be as an inequality?

Reptile [31]

at most is either that number or less

so x<=72 would be the inequality

6 0

2 years ago

Prove that √2 +√5 is irrational

Sindrei [870]

We have to prove that $\sqrt{2}+\sqrt{5}$ is irrational. We can prove this statement by contradiction.

Let us assume that $\sqrt{2}+\sqrt{5}$ is a rational number. Therefore, we can express:

$a=\sqrt{2}+\sqrt{5}$

Let us represent this equation as:

$a-\sqrt{2}=\sqrt{5}$

Upon squaring both the sides:

$(a-\sqrt{2})^{2}=(\sqrt{5})^{2}\\a^{2}+2-2\sqrt{2}a=5\\a^{2}-2\sqrt{2}a=3\\\sqrt{2}=\frac{a^{2}-3}{2a}$

Since a has been assumed to be rational, therefore, $\frac{a^{2}-3}{2a}$ must as well be rational.

But we know that $\sqrt{2}$ is irrational, therefore, from equation $\sqrt{2}=\frac{a^{2}-3}{2a}$ the expression $\frac{a^{2}-3}{2a}$ must be irrational, which contradicts with our claim.

Therefore, by contradiction, $\sqrt{2}+\sqrt{5}$ is irrational.

4 0

2 years ago