Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
1/2(4x-2)-2/3(6x+9)
(2x-1)-(4x+6)
2x-1-4x+62x-4x-1+6
-2x+5=2.5
So I believe that it is greater than 4
Answer:
Step-by-step explanation:
(4/5)n = (2/3)
move 4/5 to the right
n = (2/3)/(4/5)
n = 5/6
Answer:
7.12
Step-by-step explanation:
The formula for the effective annual yield is given as:
i = ( 1 + r/m)^m - 1
Where
i = Effective Annual yield
r = interest rate = 7% = 0.07
m= compounding frequency = semi annually = 2
i = ( 1 + 0.07/2)² - 1
i = (1 + 0.035)² - 1
= 1.035² - 1
= 1.071225 - 1
= 0.071225
Converting to percentage
0.071225 × 100
= 7.1225%
Approximately to 2 decimal places = 7.12
Therefore, the annual effective yield = 7.12
<u>Corrected question :</u>
Solve the equation. Write your answer as an integer or simplified fraction.
<u>Required Solution :</u>
The given equation,
★ Multiplying -7 into (n - 2),
>> 8n - 7 × (n - 2) = 18
>> 8n - 7n + 14 = 18
★ On substracting 7n from 8n we gets,
>> n + 14 = 18
★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),
>> n = 18 - 14
>> n = 14
★ Therefore,
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