Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
Answer:
The correct answer is 10+6p
Step-by-step explanation:
The mistake is that for the first step instead of distributing 2 to 3p and 1 they added 8+2 first. your actually supposed to distribute and get, 8+6p+2, then combine like terms and get 10+6p
Step-by-step explanation:
- 90-27=63°
- <2
- <2,<4
- 360°
Answer:
7?
Step-by-step explanation:
I think...
Answer:
the constant rate of change is 20