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Zina [86]
3 years ago
12

Write a response to the following using Claim, Evidence, Reasoning.

Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer:

The answer is A 21

Step-by-step explanation:

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LenKa [72]

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lets say 4 is a and 2 is b.

Step-by-step explanation:

add a and b. find factors.

a = half of the 57.14 dollars

b = the other half

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This case will give you 52 dollars % tax

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Step-by-step explanation:

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Plz help me will give the crown to the person who puts it right
ICE Princess25 [194]
Jus plot the points in then draw a line through them.
I will attach a graph example of it
The slope is the rate of change
You can find it in two ways
1: visually, draw a triangle and count from vertically to horizontally
2: slope formula - I will show it this way
(Y2-y1)/(x2-x1)
Given points (3,12), (4,16)
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The slope represents the $ per hour. In this case, the wage is $4 per hour.

3 0
3 years ago
Classify each of the following rational or irrational
romanna [79]

In mathematics, a rational number is any number that can be expressed as a ratio​ of two integers numbers, being a non-zero denominator.

Answers​

-5 is rational because can be writen as -5/1​

√11 is irrational because can't be written as a ratio.​

2/3 is rational because is a ratio of two integer numbers.​

0.5 is rational because can be written 1/2​

√16 is rational because can be written 4/1​

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\textit{\textbf{Spymore}}​​

7 0
3 years ago
In Exercises 1 and 2, find the equilibrium solutions of the differential equation specified.1) dy/dt = (y + 3)/(1 - y)2) dy/dt =
Aleks [24]

Answer:

1. Equilibrium solution: y= -3

2. Equilibrium solution y= ±1.414

Step-by-step explanation:

Thinking process:

The equilibrium solution can only be derived when \frac{dy}{dt}  = 0

1. Let's look at the first equation:

\frac{dy}{dt} = \frac{(y+3)}{(1-y)}

equating \frac{dy}{dt}  = 0 to the expression \frac{(y+3)}{(1-y)} gives

y + 3 = 0

     y = -3

Therefore, the equilibrium solution occurs at y = -3

2. Let's look at the second solution:

\frac{dy}{dy} = \frac{(t^{2}- 1) (y^{2}-2) }{y^{2}-4 }

dividing each side by (t²-1) gives

1/(t²-1)\frac{dy}{dt} = (y²-2)/ (y²-4)

factorizing the right hand side gives:

at equilibrium:  \frac{dy}{dt}  = 0, then

y² - 2 = 0

solving for y gives y = ±√2

                                 = ±1.414

5 0
4 years ago
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